![]() In this case a, b and c are non negative integers and for that x, y and z becomes natural numbers or positive integers.Ĭase c) In this case we substitute x = a + 2, y = b + 2 and z = c + 2, where a, b and c are non negative integers and x, y and z are greater than or equal to 2. So putting value of x, y and z in equation x + y + z = 50 we get a + b + c = 47 where n = 47 and r = 3. Means mathematically we transform x = a + 1, y = b + 1 and z = c + 1, where a, b and c are non negative integers. In this case we will one – one ball to each student and then we will distribute remaining balls in any way. So, it can be done in 52C 2 ways.Ĭase b) Let us assume we have fifty identical balls which we have to distribute between three students x, y and z such that each student can get at least one ball. This is equivalent to non negative integral solution of equation x + y + z = 50 where n = 50 and r = 3. ![]()
0 Comments
Leave a Reply. |
Details
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |